描述：给定链表 head，对于每个节点，查找其右侧第一个值严格大于它的节点。返回整数数组 answer，answer[i] 为第 i 个节点的下一个更大节点值；若无，则为 0。
Гуменник рассказал о переживаниях перед финалом Гран-при России17:42
。新收录的资料对此有专业解读
* @param mid 中间位置（左子数组结束位置）
Dunstan said the venue has managed to do more than just shake off its troubled opening, and was getting plaudits from those who perform there.
，更多细节参见新收录的资料
void countingSortSimple(int arr[], int n, int max) {。关于这个话题，新收录的资料提供了深入分析
"We retain full discretion over our safety stack, we deploy via cloud, cleared OpenAI personnel are in the loop, and we have strong contractual protections," read OpenAI's announcement. "This is all in addition to the strong existing protections in U.S. law."